A ball is kicked at 30° to the horizontal at a speed of 15ms-1 from a point 21 m above the ground where it lands.Find the horizontal range.In order to find the horizontal range you have to find the vertical time of flight. Then use s = u t.
Use s = ut + ½at2 to give-21 = (15sin30)t + ½(-9.81)t2 giving
The horizontal range is (15cos30)t = 13.0 × 2.97 = 38.6 m.
| t = | 15sin30 + √[(-15sin30)2 - 4(4.905)(-21)] 2(4.905) |
| = | 2.97s |