A cannonball is fired horizontally at 15ms-1 from a cliff that is 21m high. Calculate the time taken to hit the ground and the speed at which the cannonball hits the ground and the horizontal range.
Vertically, u=0. So the ball effectively drops vertically and we can use s = ½at2.so t = 2.07sFor the vertical velocity at which it hits the ground use v2 = 2as therefore v = 20.3ms-1. Combining this with the 15ms-1 horizontal velocity by Pythagoras, the speed at which it hits the ground is √(152 + 20.32) = 25.2ms-1. The horizontal range is given by s = ut. The time of flight is 2.07seconds and u=15ms-1. The horizontal range is 31.0m.
Horizontal Throws
Read the text
Read the text and highlight anything you think is important. When you go on, the text is hidden and you answer from memory.
Specification: Edexcel Physics (8PH0), AS-level, Topic 2: Mechanics. Topic: Motion.
More in Motion
- Constant Acceleration Question 2
- Resolving Vectors
- Resolving Vectors at an Angle
- Projectile Motion
- Vertical throws
- Throwing Upwards and Forwards
- Projectile - Question 1
- Projectile - Question 2
All 31 lessons in Motion · All Edexcel AS-level Physics topics