The luminosity L of a star is the total power it emits as electromagnetic radiation, in watts. For a black body it is given by the Stefan-Boltzmann law:L = σAT4 where σ is the Stefan-Boltzmann constant, 5.67 × 10−8 W m−2 K−4, A is the surface area in m2 and T is the surface temperature in kelvin.A star is a sphere, so A = 4πr2 andL = 4πr2σT4 Because L depends on T4, temperature has a huge effect: doubling the temperature multiplies the luminosity by 24 = 16. Luminosity is also proportional to r2, so a star three times the radius at the same temperature is 9 times as luminous. This is why cool red giants can still be very luminous: they are enormous.Worked example: the Sun has radius 6.96 × 108 m and surface temperature 5800 K. Find its luminosity.A = 4π(6.96 × 108)2 = 6.09 × 1018 m2 L = 5.67 × 10−8 × 6.09 × 1018 × 58004 = 3.9 × 1026 W Always convert temperatures to kelvin before using the law, and take care to raise T (not σAT) to the fourth power.
Stefan-Boltzmann Law
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Specification: Edexcel Physics (9PH0), A-level, Topic 10: Space. Topic: Space.
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