Nitration puts a nitro group, NO2, onto a benzene ring. It is an electrophilic substitution.Reagents and conditions: benzene is warmed with a mixture of concentrated nitric acid and concentrated sulfuric acid (the nitrating mixture) at about 50 °C. The temperature must be kept at or below this: at higher temperatures more than one nitro group is substituted, giving 1,3-dinitrobenzene.Forming the electrophile. The sulfuric acid reacts with the nitric acid to form the electrophile NO2+, the nitronium ion:HNO3 + H2SO4 → NO2+ + HSO4− + H2O At the end of the reaction the H+ released from the ring reacts with HSO4− to regenerate H2SO4, so sulfuric acid acts as a catalyst.Overall equation:C6H6 + HNO3 → C6H5NO2 + H2O The product, nitrobenzene, is a pale yellow oily liquid.Worked example: what is the maximum mass of nitrobenzene from 7.8 g of benzene? Moles of benzene = 7.8 ÷ 78 = 0.10 mol. The ratio is 1 : 1, so 0.10 mol of nitrobenzene (Mr = 123) forms: 0.10 × 123 = 12.3 g.The step-by-step mechanism is covered in the next lesson.
Nitration of Benzene
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Specification: AQA Chemistry (7405), A-level, 3.3.10.2 Electrophilic substitution. Topic: Aromatic Chemistry.
More in Aromatic Chemistry
- The Delocalised Model of Benzene
- Evidence for Delocalisation - Enthalpy of Hydrogenation
- Naming Aromatic Compounds
- Electrophilic Substitution
- Mechanism of Nitration
- Uses of Nitration
- Friedel-Crafts Acylation
- Mechanism of Friedel-Crafts Acylation
All 11 lessons in Aromatic Chemistry · All AQA A-level Chemistry topics