Skip to content

Water Potential, Turgor Pressure and Osmotic Potential

The water potential of a plant cell has two parts: the effect of the solutes and the effect of the pressure of the cell wall. They are simply added together:
ψ = ψs + ψp
where ψ is the water potential, ψs is the solute potential (osmotic potential, π, always zero or negative) and ψp is the pressure potential (turgor pressure, P, usually positive). Using the older symbols, ψ = π + P. All values are in kPa.Worked example 1: a cell has ψs = −800 kPa and ψp = +300 kPa. ψ = −800 + 300 = −500 kPa.Worked example 2: a cell has ψ = −600 kPa and ψs = −1000 kPa. Rearranging, ψp = ψ − ψs = −600 − (−1000) = +400 kPa.Two special cases:
• Fully turgid cell in pure water: water enters until ψp exactly balances ψs, so ψ = 0 kPa, the same as the water, and net movement stops.
• Incipient plasmolysis: the protoplast no longer presses on the wall, so ψp = 0 and ψ = ψs.Worked example 3: cell A has ψs = −700 kPa and ψp = +400 kPa, so ψ = −300 kPa. Cell B has ψs = −900 kPa and ψp = +300 kPa, so ψ = −600 kPa. Water moves from A to B, because A has the higher water potential.Always compare total water potentials, not solute potentials alone, when deciding the direction of osmosis between plant cells.

Read the text

Read the text and highlight anything you think is important. When you go on, the text is hidden and you answer from memory.