Atoms that absorb u.v. light and become excited are able to emit visible light when they de-excite.This is because an atom in the excited state can de-excite directly or indirectly to the ground state.The atoms emit photons of less energy by de-excitation in stages.A mercury atom in the ground state can absorb a photon of 6.7eV and then de-excite to 4.9eV emitting a photon of 1.8eV and then a photon of 4.9eV to return to the ground state.
When the ultraviolet source is removed the atoms stop glowing.
Fluorescence
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Specification: AQA Physics (7407), AS-level, 3.2.2.3 Energy levels and photon emission. Topic: The Photoelectric Effect.
More in The Photoelectric Effect
- Energy of Electrons
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- Excitation Using Photons
- De-excitation
- Fluorescent Tube
- Line Spectra
- Excitation of Hydrogen Atoms
- The Discovery of Helium
All 19 lessons in The Photoelectric Effect · All AQA AS-level Physics topics