In a homogeneous system all the species are in the same phase, so every reactant and product appears in the Kc expression.Example 1: the Haber process.N2(g) + 3H2(g) ⇌ 2NH3(g) Kc = [NH3]2 / [N2][H2]3 Units: (mol dm−3)2 / (mol dm−3)4 = (mol dm−3)−2 = dm6 mol−2.Example 2: esterification. All four substances are liquids in one mixture, so water is included:CH3COOH(l) + C2H5OH(l) ⇌ CH3COOC2H5(l) + H2O(l) Kc = [CH3COOC2H5][H2O] / [CH3COOH][C2H5OH] The units cancel, so Kc has no units.Worked example. For H2(g) + I2(g) ⇌ 2HI(g) at a certain temperature, the equilibrium concentrations are [H2] = 0.10 mol dm−3, [I2] = 0.10 mol dm−3 and [HI] = 0.70 mol dm−3.Kc = 0.702 / (0.10 × 0.10) = 0.49 / 0.010 = 49 Kc has no units. Its value is well above 1, so the equilibrium lies to the right.Always use concentrations, not moles, unless the units cancel so that the volume makes no difference.
Homogeneous Systems
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Specification: Edexcel Chemistry (8CH0), AS-level, Topic 10: Equilibrium I. Topic: Reversible Reactions and Dynamic Equilibrium.
Key terms in this lesson
- equilibrium constant
- A value, Kc, expressing the ratio of product to reactant concentrations at equilibrium for a reaction at a given temperature.
More in Reversible Reactions and Dynamic Equilibrium
- Effect of Catalysts
- Limitations of Predictions
- Homogeneous and Heterogeneous Equilibria
- The Equilibrium Law
- Heterogeneous Systems
- Industrial Processes
- The Contact Process
- Exam-Style Questions - 1
All 18 lessons in Reversible Reactions and Dynamic Equilibrium · All Edexcel AS-level Chemistry topics