Consider an object travelling with uniform circular motion at speed v moving in a short time-interval δt along the perimeter of a circle radius r. Let the distance moved by the object in that time be δs. If the distance is small, then δs can be considered to be a straight line.By similar triangles δv/v = δs/rSince v = δs/δt then δs can be replaced by vδt. Rearranging gives a = v2/r
Proof - centripetal acceleration
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Specification: OCR Physics A (H556), A-level, 5.2.2 Centripetal force. Topic: Circular Motion.
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