In radioactive decay, energy is released. The total mass of all the decay products after the decay is less than the total mass of the nucleus before the decay as some of the mass has been converted to the energy released.The relationship between the energy released Q and the difference in mass Δm is that Q = Δmc2 where c is the speed of light in a vacuum.One atomic mass unit = 1.661 x 10-27kg = 931.5 MeV.In alpha decay the energy is shared between the recoiling nucleus and the emitted alpha-particle.In beta-decay the energy is shared between the nucleus, the beta-particle, neutrino or anti-neutrino.In electron capture, the energy is transferred to the kinetic energy of the neutrino and an X-ray photon that is emitted.Worked ExampleCalculate the energy released in joules by the decay of one radon-220 nucleus.
mass of 220Rn nucleus = 219.96410umass of 216Po nucleus = 215.95572umass of α particle = 4.00150uSolution:Subtract the mass of the products from the mass of the radon nucleus.difference in mass =219.96410 - (215.95572+4.00150)=6.88×10-3uConvert atomic mass units to joules: multiply by 1u=1.661×10-27 × c2Energy in joules =6.88 ×10-3 × 1.661×10-27 × 9×1016=1.03×10-12J
Mass-Energy Equivalence
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Specification: AQA Physics (7408), A-level, 3.8.1.6 Mass and energy. Topic: Nuclear Energy.
More in Nuclear Energy
- Strong Nuclear Force
- Binding Energy and Nuclear Stability
- Quantum Tunnelling
- Nuclear Fission
- Nuclear Fusion
- Nuclear Reactors
- Safety
All 8 lessons in Nuclear Energy · All AQA A-level Physics topics