Organic compounds are named using the IUPAC system, so each name describes exactly one structure.1. Find the longest carbon chain (it must contain the functional group). This gives the stem: meth (1 C), eth (2), prop (3), but (4), pent (5), hex (6), hept (7), oct (8), non (9), dec (10).2. Add the suffix for the main functional group: -ane for alkanes, -ene for alkenes, -ol for alcohols, -al for aldehydes, -one for ketones and -oic acid for carboxylic acids.3. Add prefixes for side chains and halogens: methyl (CH3), ethyl (C2H5), fluoro, chloro, bromo and iodo.4. Number the chain from the end that gives the functional group, or the substituents, the lowest numbers.5. Write the name: substituents go in alphabetical order; use di-, tri- and tetra- when a group appears more than once; separate numbers from each other with commas and numbers from letters with hyphens.Worked examples:
CH3CH(CH3)CH2CH3: longest chain 4 C (butane), methyl on C2, so 2-methylbutane (not 3-methylbutane).
CH3CH(OH)CH3: 3 C chain, OH on C2, so propan-2-ol.
CH2=CHCH2CH3: 4 C chain, C=C starts at C1, so but-1-ene.
CH2ClCH2Cl: 2 C chain, Cl on C1 and C2, so 1,2-dichloroethane.
CH3C(CH3)2CH3: 3 C chain, two methyls on C2, so 2,2-dimethylpropane.
CH3CH(CH3)CH2CH3: longest chain 4 C (butane), methyl on C2, so 2-methylbutane (not 3-methylbutane).
CH3CH(OH)CH3: 3 C chain, OH on C2, so propan-2-ol.
CH2=CHCH2CH3: 4 C chain, C=C starts at C1, so but-1-ene.
CH2ClCH2Cl: 2 C chain, Cl on C1 and C2, so 1,2-dichloroethane.
CH3C(CH3)2CH3: 3 C chain, two methyls on C2, so 2,2-dimethylpropane.