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Exam Question 5

QuestionSome of the energy levels of a hydrogen atom are: n = 1: −13.6 eV, n = 2: −3.40 eV, n = 3: −1.51 eV.(a) Explain why the energy levels have negative values. (1)
(b) An electron falls from n = 2 to n = 1. Calculate the wavelength of the photon emitted and state the region of the electromagnetic spectrum it is in. (4)
(c) State how many different photon energies can be emitted by electrons de-exciting from n = 3 to the ground state. (1)Answer(a) Zero energy is defined as an electron that is free of the atom. Energy must be supplied to free a bound electron, so a bound electron has less than zero energy. (1)(b) ΔE = −3.40 − (−13.6) = 10.2 eV (1)ΔE = 10.2 × 1.60 × 10-19 = 1.63 × 10-18 J (1)
λ = hc / ΔE = (6.63 × 10-34 × 3.00 × 108) ÷ 1.63 × 10-18 = 1.22 × 10-7 m

(1)This is 122 nm, which is in the ultraviolet region. (1)(c) Three: 3 → 1, 3 → 2 and 2 → 1. (1)Examiner tips- The photon energy is always the positive difference between the two levels. Take care with the minus signs.
- Convert eV to J before using λ = hc / ΔE.
- Visible light is roughly 400 nm to 700 nm. In hydrogen, falls to n = 1 give ultraviolet photons, while falls to n = 2 give mainly visible light.

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Specification: Edexcel Physics (8PH0), AS-level, Topic 5: Waves and Particle Nature of Light. Topic: Quantum Physics.

Key terms in this lesson

energy level
One of the discrete, fixed values of energy that an electron in an atom can have.
ground state
The lowest, most stable energy level of an electron in an atom.

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