BRAINCAKEExponential Decay.
When the charge on capacitor C decreases by ΔQ through fixed resistor R in time Δt, I = V/R where V = Q/C. This means that I = Q/RC and ΔQ the change in charge becomes -QΔt/CR.
Sign in free to see the rest of this lesson, the R.E.C.I.P.E. recall steps and the quiz
BrainCake is free. Make an account in seconds and pick up where this page stops.
More in Capacitors
- Use of Capacitors
- Energy Stored in a Charged Capacitor
- Measuring the Energy Stored in a Charged Capacitor.
- Energy stored in a Thundercloud
- Discharging a Capacitor through a Fixed Resistor
- The Time Constant RC
- Measurement with Oscilloscope. Capacitor Smoothing
- Charging a Capacitor through a fixed resistor
All 12 lessons in Capacitors · All AQA A-level Physics topics