For the formation of butane from its elements in their standard states,4C(s) + 5H2(g) → C4H10(g)The enthalpy of formation of butane would be impossible to measure because carbon and hydrogen form so many compounds alongside butane.The enthalpy of formation can be determined from the enthalpies of combustion of the reactants and products.4C(s) + 5H2(g) → C4H10(g)
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4CO2 + 5H2OΔHf butane = 4 x ΔHc carbon + 5 x ΔHc hydrogen- ΔHc butane
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4CO2 + 5H2OΔHf butane = 4 x ΔHc carbon + 5 x ΔHc hydrogen- ΔHc butane