This worked example finds the overall percentage uncertainty in a titration result.Question: a 25.0 cm3 pipette (± 0.06 cm3) is used to transfer sodium hydroxide to a conical flask. The burette (± 0.05 cm3 per reading) reads 0.00 cm3 at the start and 23.40 cm3 at the end point. Calculate the total percentage uncertainty from the volume measurements.Step 1: uncertainty in the titre. The titre comes from two readings, so the uncertainties add:uncertainty = 0.05 + 0.05 = ± 0.10 cm3percentage uncertainty = (0.10 ÷ 23.40) × 100 = 0.43%Step 2: uncertainty in the pipette volume. The pipette is filled to one mark, so its tolerance is used once:percentage uncertainty = (0.06 ÷ 25.0) × 100 = 0.24%Step 3: combine. The concentration is calculated by multiplying and dividing these volumes, so the percentage uncertainties add:total = 0.43 + 0.24 = 0.67%Interpreting the result: the burette is the larger contributor. If the concentrations were changed so the titre was only about 12 cm3, its percentage uncertainty would roughly double to about 0.8%. That is why titrations are designed to give titres in the range of about 20 to 30 cm3.If the standard solution also has a stated uncertainty in its concentration, add that percentage to the total as well.
Example Calculation - 3
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Specification: Edexcel Chemistry (8CH0), AS-level. Topic: Errors and Uncertainties.
Key terms in this lesson
- titre
- The volume of solution, usually read from a burette, needed to reach the end point of a titration.
More in Errors and Uncertainties
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- Minimising Errors and Uncertainties
- Percentage Yield
- Atom Economy
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- Example Calculation - 2
- Example Calculation - 4
All 14 lessons in Errors and Uncertainties · All Edexcel AS-level Chemistry topics