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Example Question - 2

Question: A hydrocarbon contains 85.7% carbon and 14.3% hydrogen by mass. Its relative molecular mass is 42. Find its molecular formula. (Ar: C = 12, H = 1)Step 1: find the empirical formula. Divide each percentage by the relative atomic mass.
C: 85.7 ÷ 12 = 7.14     H: 14.3 ÷ 1 = 14.3
Divide both by the smallest value (7.14):
C: 1     H: 14.3 ÷ 7.14 = 2.00
The empirical formula is CH2.Step 2: find the mass of one empirical formula unit.
CH2 = 12 + (2 × 1) = 14
Step 3: find how many empirical units are in one molecule.
n = Mr ÷ empirical formula mass = 42 ÷ 14 = 3
Step 4: multiply every number in the empirical formula by n.
(CH2)3 = C3H6
Answer: the molecular formula is C3H6.Check: Mr of C3H6 = (3 × 12) + (6 × 1) = 42, which matches the value given.The value of n must always come out as a whole number. If it does not, recheck the empirical formula. The Mr is usually given in the question or found from the molecular ion peak in a mass spectrum.

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Specification: Edexcel Chemistry (8CH0), AS-level, Topic 5: Formulae, Equations and Amounts of Substance. Topic: Amount of Substance and Calculations.

Key terms in this lesson

empirical formula
The simplest whole number ratio of atoms of each element in a compound.
molecular formula
The actual number of atoms of each element in one molecule of a compound.

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