Sulfur dioxide reacts with oxygen to form sulfur trioxide.2 SO2(g) + O2(g) ⇌ 2 SO3(g)A mixture of gases forms containing 0.025 mol of sulfur dioxide, 0.049 mol of oxygen and 0.034 mol of sulfur trioxide.The total pressure of the mixture in a 3500 cm3 reaction vessel is 255 kPa. Use the data to calculate the temperature, in °C, of the mixture.The ideal gas constant, R = 8.31 J K−1 mol−1
solution:pV = nRTn = 0.025 + 0.049 + 0.034n = 0.108Conversions: pressure = 255000 Pa; volume = 0.0035 m3T = pV ÷ nR =(255000 × 0.0035) ÷ (8.31 × 0.108)T = 994.5 KT = 721 °C
solution:pV = nRTn = 0.025 + 0.049 + 0.034n = 0.108Conversions: pressure = 255000 Pa; volume = 0.0035 m3T = pV ÷ nR =(255000 × 0.0035) ÷ (8.31 × 0.108)T = 994.5 KT = 721 °C