Free-radical substitution does not stop after one hydrogen has been replaced. A chlorine radical can remove a hydrogen from chloromethane, leading to further substitution.For example: CH3Cl + Cl• → •CH2Cl + HCl, then •CH2Cl + Cl2 → CH2Cl2 + Cl•Repeating this gives trichloromethane, CHCl3, and tetrachloromethane, CCl4. The overall equation for complete substitution is CH4 + 4Cl2 → CCl4 + 4HCl.The reaction therefore gives a mixture of products, which is a disadvantage. Termination steps also make other products, such as ethane or chloroethane.Using excess methane makes it more likely that a chlorine radical hits a methane molecule, so it favours CH3Cl. The products can be separated by fractional distillation.
Further Substitution
Read the text
Read the text and highlight anything you think is important. When you go on, the text is hidden and you answer from memory.
Specification: AQA Chemistry (7404), AS-level, 3.3.2.4 Chlorination of alkanes. Topic: Alkanes.
More in Alkanes
- Combustion
- Polluting the Atmosphere
- Flue Gas Desulfurisation
- Catalytic Converters
- Greenhouse Effect
- Carbon Neutral Activities
- Free-Radical Substitution
- Ozone Layer
All 20 lessons in Alkanes · All AQA AS-level Chemistry topics