Alcohols can be oxidised by acidified potassium dichromate(VI): potassium dichromate(VI), K2Cr2O7, with dilute sulfuric acid.When the alcohol is oxidised, the orange dichromate(VI) ions are reduced to green chromium(III) ions:Cr2O72− (orange) → Cr3+ (green) This colour change shows that oxidation has taken place.In equations the oxidising agent is written as [O], which stands for an oxygen atom from the oxidising agent. The equation must still balance. Oxidation removes two hydrogen atoms: one from the -OH group and one from the carbon bonded to it. These combine with [O] to form water.What an alcohol forms depends on its class:
Primary alcohols are oxidised to aldehydes, which can be oxidised further to carboxylic acids.
Secondary alcohols are oxidised to ketones.
Tertiary alcohols are not easily oxidised, because the C-OH carbon has no hydrogen atom to lose. The dichromate stays orange.Worked example: write the equation for the oxidation of propan-2-ol.
Propan-2-ol, CH3CH(OH)CH3, loses 2 H atoms, which join [O] to form H2O:CH3CH(OH)CH3 + [O] → CH3COCH3 + H2O The product is propanone, a ketone.The colour change can therefore be used to tell tertiary alcohols apart from primary and secondary alcohols.
Primary alcohols are oxidised to aldehydes, which can be oxidised further to carboxylic acids.
Secondary alcohols are oxidised to ketones.
Tertiary alcohols are not easily oxidised, because the C-OH carbon has no hydrogen atom to lose. The dichromate stays orange.Worked example: write the equation for the oxidation of propan-2-ol.
Propan-2-ol, CH3CH(OH)CH3, loses 2 H atoms, which join [O] to form H2O: