BRAINCAKEFinding the Value of Kc
0.1mol of ethanol is mixed with 0.1mol of ethanoic acid and allowed to reach equilibrium. The total volume of the system is made up to 20.0cm3 with water. By titration it was found that 0.033mol of ethanoic acid was present at equilibrium. At the start, 0.033mol of ethanoic acid is left at equilibrium so (0.1 - 0.033)mol must have reacted.(0.1 - 0.033) = 0.067 so 0.067mol of ethanoic acid has reacted with 0.067mol of ethanol to form 0.067mol of water and 0.067mol of ethyl ethanoate since the ratios are 1: 1: 1: 1 at equilibrium.
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