Skip to content

Synthetic Routes - Aromatic Compounds

Aromatic compounds contain a benzene ring. Benzene's delocalised ring is very stable, so it reacts by electrophilic substitution, which keeps the ring intact. For AQA, two reactions of benzene start almost every aromatic route.1. Nitration: concentrated HNO3 and concentrated H2SO4, at about 50 °C. The acids form the nitronium ion, NO2+, which substitutes for an H on the ring to give nitrobenzene, C6H5NO2. Keeping the temperature low limits further nitration.2. Friedel-Crafts acylation: an acyl chloride with an AlCl3 catalyst, heated under reflux. The electrophile RCO+ substitutes onto the ring to give a phenyl ketone, C6H5COR. This is how a new C-C bond is made to the ring.The new groups can then be converted further:
• nitrobenzene + tin and concentrated HCl, then NaOH → phenylamine, C6H5NH2 (a reduction)
• phenylamine + acyl chloride or acid anhydride → N-substituted amide
• phenyl ketone + NaBH4 → secondary alcohol, C6H5CH(OH)R
• phenyl ketone + KCN, then dilute acid → hydroxynitrileWorked example. Plan a two-step synthesis of 1-phenylethanol, C6H5CH(OH)CH3, from benzene. The CH(OH)CH3 group comes from reducing the ketone C6H5COCH3. Step 1: benzene + ethanoyl chloride with AlCl3 catalyst → phenylethanone. Step 2: NaBH4 → 1-phenylethanol.At A level you never build a benzene ring, so an aromatic target needs an aromatic starting material.

Read the text

Read the text and highlight anything you think is important. When you go on, the text is hidden and you answer from memory.