Ecological efficiency can be calculated for any transfer, as long as both values are in the same units (biomass or energy, per unit area per year).ecological efficiency (%) = (biomass or energy transferred to the higher trophic level ÷ biomass or energy in the lower trophic level) × 100 Worked example 1: grass has 8000 kJ m−2 yr−1 of NPP. The rabbits eating it gain 800 kJ m−2 yr−1.
Efficiency = (800 ÷ 8000) × 100 = 10%.Worked example 2: a pond food chain.
Producers: 87 000 kJ m−2 yr−1
Primary consumers: 14 000 kJ m−2 yr−1
Secondary consumers: 1600 kJ m−2 yr−1
Producers to primary consumers: (14 000 ÷ 87 000) × 100 = 16.1%.
Primary to secondary consumers: (1600 ÷ 14 000) × 100 = 11.4%.Working backwards: if an efficiency is known, you can find a missing value. With 10% efficiency and 5000 kJ m−2 yr−1 in the primary consumers, the secondary consumers receive 5000 × 0.10 = 500 kJ m−2 yr−1.Tips
• Always divide the higher trophic level by the lower one; the answer must be below 100%.
• Check the units match before dividing.
• Round sensibly, usually to 3 significant figures or 1 decimal place.
• Efficiencies vary a lot between ecosystems, so a figure far from 10% is not necessarily wrong.
Efficiency = (800 ÷ 8000) × 100 = 10%.Worked example 2: a pond food chain.
Producers: 87 000 kJ m−2 yr−1
Primary consumers: 14 000 kJ m−2 yr−1
Secondary consumers: 1600 kJ m−2 yr−1
Producers to primary consumers: (14 000 ÷ 87 000) × 100 = 16.1%.
Primary to secondary consumers: (1600 ÷ 14 000) × 100 = 11.4%.Working backwards: if an efficiency is known, you can find a missing value. With 10% efficiency and 5000 kJ m−2 yr−1 in the primary consumers, the secondary consumers receive 5000 × 0.10 = 500 kJ m−2 yr−1.Tips
• Always divide the higher trophic level by the lower one; the answer must be below 100%.
• Check the units match before dividing.
• Round sensibly, usually to 3 significant figures or 1 decimal place.
• Efficiencies vary a lot between ecosystems, so a figure far from 10% is not necessarily wrong.