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Moments Question 2

Question: a uniform plank of length 4.0 m and weight 200 N rests horizontally on two supports, A at the left end and B at the right end. A person of weight 600 N stands 1.0 m from A. Calculate the upward forces RA and RB from the supports.
Step 1: find the centre of gravity. The plank is uniform, so its 200 N weight acts at its midpoint, 2.0 m from A.Step 2: take moments about A. Choosing A as the pivot removes the unknown RA, because a force has no moment about the point where it acts.Clockwise moments about A = (600 × 1.0) + (200 × 2.0) = 600 + 400 = 1000 N mAnticlockwise moment about A = RB × 4.0
RB × 4.0 = 1000, so RB = 250 N
Step 3: balance the vertical forces. The plank is in equilibrium, so total upward force = total downward force.
RA + RB = 600 + 200 = 800 N
RA = 800 - 250 = 550 N
Check: taking moments about B gives RA × 4.0 = (600 × 3.0) + (200 × 2.0) = 2200 N m, so RA = 550 N, as before.The support nearer the person carries more of the load, as expected. Remember to include the weight of the beam itself: forgetting it is the most common mistake in this type of question.

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Specification: Edexcel Physics (8PH0), AS-level, Topic 2: Mechanics. Topic: Motion.

Key terms in this lesson

moment
The turning effect of a force, equal to the force multiplied by the perpendicular distance from its line of action to the pivot.
equilibrium
A state in which the resultant force and resultant moment on an object are both zero, so it has no tendency to accelerate or turn.
centre of gravity
The single point through which the whole weight of an object appears to act.

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