Momentum Question 1

P and Q are identical spheres.Sphere P moves along a smooth horizontal surface and collides with sphere Q, which is initially stationary.After the collision:• sphere P moves off with a momentum of 0.096 kg ms^-1 in a direction of 15° to its initial direction.• sphere Q moves off with momentum of 0.14kgms^-1 in a direction of 10° to P's initial direction, on the other side, as shown.Calculate the initial velocity of sphere P.mass of sphere P = 0.12kg.Answer: resolving along P's initial direction, the initial momentum of P = 0.096cos15° + 0.14cos10° = 0.0927 + 0.138 = 0.231 kg ms^-1, so the initial velocity of P = 0.231 ÷ 0.12 = 1.92 ms^-1.