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Disproportionation

Disproportionation is the simultaneous oxidation and reduction of an element in a single reaction.For example:2 Cu+ (aq) → Cu2+ (aq) + Cu (s) copper is reduced from +1 to 0 and oxidised from +1 to +2.To spot disproportionation, work out the oxidation number of the element in the reactant and in each product. If the same element starts in one oxidation state and ends up in two different ones, one higher and one lower, the reaction is a disproportionation.In the copper example, one Cu+ ion loses an electron and the other gains it:
Cu+ → Cu2+ + e−    (oxidation)

Cu+ + e− → Cu    (reduction)
So the same species acts as both the oxidising agent and the reducing agent.Another example is the decomposition of hydrogen peroxide:
2 H2O2 (aq) → 2 H2O (l) + O2 (g)
Oxygen is −1 in H2O2. It is reduced to −2 in water and oxidised to 0 in oxygen gas.Chlorine also disproportionates when it reacts with water:
Cl2 (aq) + H2O (l) → HCl (aq) + HClO (aq)
Chlorine goes from 0 to −1 in HCl and to +1 in HClO, chloric(I) acid.

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Specification: Edexcel Chemistry (8CH0), AS-level, Topic 3: Redox I. Topic: Oxidation and Reduction.

Key terms in this lesson

oxidising agent
A substance that accepts electrons from another species, causing it to be oxidised, while it is itself reduced.
reducing agent
A substance that donates electrons to another species, causing it to be reduced, while it is itself oxidised.

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