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Titration Calculations - 2

Sodium carbonate is a common standard solution because it can be weighed accurately as a pure, stable solid. It is often used to find the concentration of hydrochloric acid, with methyl orange as the indicator.
Na2CO3(aq) + 2HCl(aq) → 2NaCl(aq) + H2O(l) + CO2(g)
Here the ratio is Na2CO3 : HCl = 1 : 2, so this time you multiply by 2 to go from the carbonate to the acid.Worked example: 25.0 cm3 of 0.0500 mol dm-3 sodium carbonate solution was titrated with hydrochloric acid. The concordant titres were 20.05, 19.95 and 20.00 cm3. Calculate the concentration of the acid.Mean titre = (20.05 + 19.95 + 20.00) ÷ 3 = 20.00 cm3Step 1: amount of Na2CO3 = 0.0500 × (25.0 ÷ 1000) = 1.25 × 10-3 molStep 2: 1 mol Na2CO3 reacts with 2 mol HCl, so amount of HCl = 1.25 × 10-3 × 2 = 2.50 × 10-3 molStep 3: concentration of HCl = 2.50 × 10-3 ÷ (20.00 ÷ 1000) = 0.125 mol dm-3Compare this with the sulfuric acid example: there the unknown was the diprotic reagent and you divided by 2; here the known is the reagent that needs two moles of acid, so you multiply. Reading the ratio from the equation, rather than remembering a rule, avoids the mistake.

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Specification: Edexcel Chemistry (8CH0), AS-level, Topic 5: Formulae, Equations and Amounts of Substance. Topic: Amount of Substance and Calculations.

Key terms in this lesson

concentration
The amount of solute, in moles, dissolved in each dm3 of solution.
mole
The amount of substance containing 6.02 x 10^23 particles, the same number as the atoms in 12 g of carbon-12.

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