Many reactions produce a gas, and the molar volume lets you predict the volume of gas from the mass of a reactant. The method always has three steps:1. Find the amount of the known substance: amount = mass ÷ Mr2. Use the mole ratio from the balanced equation to find the amount of gas.3. Convert to volume: volume (dm3) = amount × 24.0 at r.t.p.Worked example 1: 2.43 g of magnesium reacts with excess hydrochloric acid. What volume of hydrogen forms at r.t.p.?Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g) amount of Mg = 2.43 ÷ 24.3 = 0.100 molratio Mg : H2 = 1 : 1, so amount of H2 = 0.100 molvolume of H2 = 0.100 × 24.0 = 2.40 dm3Worked example 2: 5.00 g of calcium carbonate is heated until it fully decomposes. What volume of carbon dioxide forms at r.t.p.?CaCO3(s) → CaO(s) + CO2(g) amount of CaCO3 = 5.00 ÷ 100.1 = 0.0500 mol, so 0.0500 mol of CO2 formsvolume of CO2 = 0.0500 × 24.0 = 1.20 dm3The calculation also works backwards: divide a measured gas volume by 24.0 to get moles, use the ratio, then multiply by Mr to find the mass of reactant used.
Molar Volume Calculation - 2
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Specification: Edexcel Chemistry (8CH0), AS-level, Topic 5: Formulae, Equations and Amounts of Substance. Topic: Amount of Substance and Calculations.
Key terms in this lesson
- molar volume
- The volume occupied by one mole of any gas at a stated temperature and pressure, 24 dm3 at rtp.
- mole
- The amount of substance containing 6.02 x 10^23 particles, the same number as the atoms in 12 g of carbon-12.
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