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Example Question - 1

When heated, a sample of potassium chlorate(V) (KClO3) produced 0.0897g of oxygen
2KClO3(s) → 2KCl(s) + 3O2(g)What is the amount, in moles, of potassium chlorate(V) that has decomposed?
moles of oxygen
= 0.0897 ÷ 32 = 2.803 × 10 -3potassium chlorate(V)
= 2.803 × 10 -3 × ⅔= 1.869 × 10 -3 mol

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Specification: AQA Chemistry (7404), AS-level, 3.1.2.5 Balanced equations and associated calculations. Topic: Amount of Substance.

Key terms in this lesson

Mole
The amount of substance that contains as many particles as there are atoms in exactly 12g of carbon-12.

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